F(-2)=4x^2+x+5

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Solution for F(-2)=4x^2+x+5 equation: 



(-2)=4F^2+F+5

We move all terms to the left:

(-2)-(4F^2+F+5)=0

We add all the numbers together, and all the variables

-(4F^2+F+5)-2=0

We get rid of parentheses

-4F^2-F-5-2=0

We add all the numbers together, and all the variables

-4F^2-1F-7=0

a = -4; b = -1; c = -7;
Δ = b2-4ac
Δ = -12-4·(-4)·(-7)
Δ = -111
Delta is less than zero, so there is no solution for the equation

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